I have a question and wish learning. It's about "Decimal Number and Solving Equation"
Thanks in advance.
Assuming that all those digits in the starting equation are actually valid, you are better off using the symbolic processor to solve it. It's more accurate.
Thanks for your help, Mike and Richard. I follow Richard's instruction and :
from (1) & (2) above, what we could say between :
Thanks in advandce,
Message was edited by: Loi Le
After solve, then substitute, x=0 above. We get :
from (7) & (8) above =>
Of course the two numbers are not strictly equal. You can tell that just by looking at them. You just don't have enough precision in the calculations to see the difference.
By default, the symbolic processor uses 20 digits of precision for floating point calculations. You can change that by using the float keyword (which does not just change the precision of the displayed result; it changes the precision used in the calculations).
I greatly appreciate your answer to my question, Richard. (A nice answer). I think I am new and have not comprehended with "float,50 ,..". Could you tell me more elaborate (as Mike said above) the following :
I got it. Many thanks, Richard. And I have one more related question :
I'm not sure what you mean. Do you mean "can it be simplified to another equivalent expression?". No. At least, not by either the Maple of the Mupad engines in MC11 and MC15. If you type ,max (note the comma!) after the keyword simplify it will give you the maximum amount of simplification the symbolic processor can do.