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1067 Views 30 Replies Latest reply: Jul 3, 2013 8:04 AM by TomD.inPDX RSS
TomD.inPDX Platinum 5,279 posts since
May 25, 2012
Currently Being Moderated

Jun 13, 2013 2:29 PM

Help!  Equation Solution Request.

How do I "define" a semi-circle by an equation when Y is linear?

 

I know the cartesian formula:

           x = 4 * cos ( t * 180 )

           y = 4 * sin ( t * 180 )

           z = 0

 

But I need to compensate for the trajectory (Y) which has a linear value.

I need the formula applied only to X given Y is linear 0-1.

 

I want to sweep a VSS to make this shape.  The trajpar is the given value (t as Y):

 

equation_question.PNG

  • VladimirPalffy Platinum 362 posts since
    Jan 25, 2009
    Currently Being Moderated
    Jun 13, 2013 10:37 PM (in response to TomD.inPDX)
    Re: Help!  Equation Solution Request.

    Dear Antonius,

    I think that you can combine Sweep feature with Graph feature - the values of graph will be inputs for sweep trajpar relations.

     

    Regards,

    Vladimir

  • VladimirN. Platinum 2,398 posts since
    Sep 26, 2010
    Currently Being Moderated
    Jun 14, 2013 11:58 PM (in response to TomD.inPDX)
    Re: Help!  Equation Solution Request.

    Hi Antonius,

     

    Maybe "Mathcad" community able to help you: http://communities.ptc.com/community/mathcad

  • FrankS.Schiavone Platinum 1,390 posts since
    Sep 8, 2011
    Currently Being Moderated
    Jun 18, 2013 9:42 AM (in response to TomD.inPDX)
    Re: Help!  Equation Solution Request.

    I'd love to help, but I **** at math!  I'd be graphing that baby! 

  • VladimirPalffy Platinum 362 posts since
    Jan 25, 2009
    Currently Being Moderated
    Jun 18, 2013 11:45 PM (in response to TomD.inPDX)
    Re: Help!  Equation Solution Request.

    Dear Antonius

    I have tried to create SEMICIRCLE BY SWEEP feature - it is working (you can investigate my model)

     

    Note: I have used for sweep feature the Relation (for UPPER_HALF_OF_THE_SEMICIRCLE) sd4=(r^2 - (trajpar*r)^2) ^ (1/2)

     

    Regards,

    Vladimir

      • VladimirPalffy Platinum 362 posts since
        Jan 25, 2009
        Currently Being Moderated
        Jun 19, 2013 11:58 AM (in response to TomD.inPDX)
        Re: Help!  Equation Solution Request.

        You are Welcome Antonius.

        It was challenge for me too - I like Relations and Sweep feature too - it is powerfull combination.

         

        Here is some old example

         

        wallpaper_creo_logo_wire.jpg

         

        Regards,

        Vladimir

          • FrankS.Schiavone Platinum 1,390 posts since
            Sep 8, 2011
            Currently Being Moderated
            Jun 26, 2013 8:18 AM (in response to TomD.inPDX)
            Re: Help!  Equation Solution Request.

            Cool stuff!  I'll definately have to look at the equations, thanks!

             

            It is the bill of a ball cap? 

                • FrankS.Schiavone Platinum 1,390 posts since
                  Sep 8, 2011
                  Currently Being Moderated
                  Jun 26, 2013 1:24 PM (in response to TomD.inPDX)
                  Re: Help!  Equation Solution Request.

                  I've seen weird things like that in boundary blends near corners.  IMO, Boundary blend was better and more robust before WF.

                    • FrankS.Schiavone Platinum 1,390 posts since
                      Sep 8, 2011
                      Currently Being Moderated
                      Jun 27, 2013 6:45 AM (in response to TomD.inPDX)
                      Re: Help!  Equation Solution Request.

                      Hmmmm, so the geometry ISN'T all weird like that?  Interesting.....

                    • James62 Platinum 596 posts since
                      Jan 22, 2011
                      Currently Being Moderated
                      Jun 27, 2013 9:34 AM (in response to TomD.inPDX)
                      Re: Help!  Equation Solution Request.

                      Does it fail to create the surface on the high quality settings if you actually confirm creation of the sweep? Or will it just create distorded surface?

                       

                      This is like really really odd. The boundary of that surface shouldn't change at all, while the mesh of the surface could of course with the different display quality.

                        • James62 Platinum 596 posts since
                          Jan 22, 2011
                          Currently Being Moderated
                          Jun 27, 2013 12:58 PM (in response to TomD.inPDX)
                          Re: Help!  Equation Solution Request.

                          That's nasty.

                           

                          Tom, could you also please show the curvature analysis of the curves in your video? Just so one can see these are not some crazy oscilating splines, but regular curves.

                                • James62 Platinum 596 posts since
                                  Jan 22, 2011
                                  Currently Being Moderated
                                  Jun 28, 2013 9:18 AM (in response to TomD.inPDX)
                                  Re: Help!  Equation Solution Request.

                                  You are welcome, I'm glad you got it working, and with so few features, really interesting approach.

                                   

                                  Actually, I never knew portion of a surface can be cut out with another on-laying surface in Creo.

                                   

                                  So, just to say again, learn something new everyday.

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